Advanced Qualification · A-003 Measurements · A-003-002-007
What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?
- A 500 watts
- B 625 watts
- C 1250 watts
- D 2500 watts
Correct answer: B — 625 watts. From the official ISED question bank, verified word for word.
Why
To find the power, first turn the 500 volts peak-to-peak into a peak voltage of 250 volts, then convert that to a root mean square value of about 177 volts, which represents the steady heating effect of the signal. The full explanation — and one for every question — is in Pro.
Practise this section
Measurements: meters, oscilloscopes, counters, signal generators, and what a reading actually tells you.