Advanced Qualification · A-003 Measurements · A-003-002-006
What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output?
- A 100 watts
- B 400 watts
- C 1000 watts
- D 200 watts
Correct answer: A — 100 watts. From the official ISED question bank, verified word for word.
Why
To find the power, first halve the 200 volts peak-to-peak to get 100 volts peak, then divide by the square root of two to find the root-mean-square voltage, which represents the effective heating value. The full explanation — and one for every question — is in Pro.
Practise this section
Measurements: meters, oscilloscopes, counters, signal generators, and what a reading actually tells you.